In the reaction,the acid obtained will be CH_ | vedclass

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(D) The reaction involves the nucleophilic addition of $HCN$ to acetaldehyde $(CH_3CHO)$.The carbonyl carbon in $CH_3CHO$ is $sp^2$ hybridized and pla

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$(50\% \,D + 50\% \,L)$ mixture

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(D) The reaction involves the nucleophilic addition of $HCN$ to acetaldehyde $(CH_3CHO)$.The carbonyl carbon in $CH_3CHO$ is $sp^2$ hybridized and planar.The cyanide ion $(CN^-)$ can attack the carbonyl carbon from either the top or the bottom face with equal probability.This leads to the formation of a racemic mixture of the cyanohydrin intermediate,which upon hydrolysis yields a racemic mixture of $2$-hydroxypropanoic acid (lactic acid).$A$ racemic mixture consists of an equal amount of $D$ and $L$ isomers,i.e.,a $(50\% \,D + 50\% \,L)$ mixture.

In the reaction,the acid obtained will be
$CH_3CHO + HCN \to CH_3CH(OH)CN \xrightarrow{H_2O} CH_3CH(OH)COOH$

Similar Questions

What is the product of the Clemmensen reduction of $3-nitroacetophenone$?

Which of the following compounds gives only a primary alcohol on reaction with a Grignard reagent $(RMgX)$?

The aldehydes which will not form a single Grignard product with one equivalent of Grignard reagent are:
$(a)$ Benzaldehyde
$(b)$ $4$-Formylbenzoic acid
$(c)$ $4$-Methoxybenzaldehyde
$(d)$ $4$-(Hydroxymethyl)benzaldehyde

The reactant is $3$-methylpentanal. The reaction with $NaCN$ followed by $H_2SO_4$ (cyanohydrin formation) is shown below:
$CH_3CH_2CH(CH_3)CH_2CHO \xrightarrow{NaCN/H^+} CH_3CH_2CH(CH_3)CH_2CH(OH)CN$
Products of the reaction are:

Assertion : Benzaldehyde is more reactive than ethanol towards nucleophilic attack.
Reason : The overall effect of $-I$ and $+R$ effect of phenyl group decreases the electron density on the carbon atom of $>C=O$ group in benzaldehyde.

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In the reaction,the acid obtained will be $CH_3CHO + HCN \to CH_3CH(OH)CN \xrightarrow{H_2O} CH_3CH(OH)COOH$